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5s^2+35s+42=0
a = 5; b = 35; c = +42;
Δ = b2-4ac
Δ = 352-4·5·42
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{385}}{2*5}=\frac{-35-\sqrt{385}}{10} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{385}}{2*5}=\frac{-35+\sqrt{385}}{10} $
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